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4.9x^2-7x-160=0
a = 4.9; b = -7; c = -160;
Δ = b2-4ac
Δ = -72-4·4.9·(-160)
Δ = 3185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3185}=\sqrt{49*65}=\sqrt{49}*\sqrt{65}=7\sqrt{65}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7\sqrt{65}}{2*4.9}=\frac{7-7\sqrt{65}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7\sqrt{65}}{2*4.9}=\frac{7+7\sqrt{65}}{9.8} $
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